0=x^2-125x-600

Solution for 0=x^2-125x-600 equation:

0=x^2-125x-600

We move all terms to the left:

0-(x^2-125x-600)=0

We add all the numbers together, and all the variables

-(x^2-125x-600)=0

We get rid of parentheses

-x^2+125x+600=0

We add all the numbers together, and all the variables

-1x^2+125x+600=0

a = -1; b = 125; c = +600;
Δ = b2-4ac
Δ = 1252-4·(-1)·600
Δ = 18025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{18025}=\sqrt{25*721}=\sqrt{25}*\sqrt{721}=5\sqrt{721}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(125)-5\sqrt{721}}{2*-1}=\frac{-125-5\sqrt{721}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(125)+5\sqrt{721}}{2*-1}=\frac{-125+5\sqrt{721}}{-2}
$